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ORACLE 1z0-071 Certification Exam is an Oracle Database 12c Database Administrator (DBA) certification exam. Oracle 1z0-071 DBA certification is a prerequisite for other exams in the business and technical areas of Database Administration. In this article, we are going to discuss the Oracle 1Z0-071, basic information about this exam, and the best Sources for the preparation of the exam. Oracle 1z0-071 Dumps is the best resource for the preparation for this certification exam. This article serves as a teaching guide to prepare you for the exam and set you up for future success and privileges.
Oracle 1z0-071 exam is a computer-based exam that consists of 73 multiple-choice questions. 1z0-071 exam has a time limit of 105 minutes, and candidates must attain a score of 63% or higher to pass. 1z0-071 exam fee is $245, and it is available in several languages including English, Japanese, and Chinese.
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Which two statements will do an implicit conversion?
A. SELECT * FROM customers WHERE customer_ id = 0001 ;
B. SELECT * FROM customers WHERE insert date ='01-JAN-19'
C. SELECT * FROM customers WHERE customer id = '0001';
D. SELECT * FROM customers WHERE TO_ CHAR (customer_ id) ='0001';
E. SELECT * FROM customers WHERE insert_ date = DATE '2019-01-01';
Answer: A,B
Explanation:
A: True. This statement will work if customer_id is a character data type in the database. Oracle will implicitly convert the numeric literal 0001 to a string to compare with customer_id.
D; True. If the insert_date is of type DATE and the NLS_DATE_FORMAT matches 'DD-MON-YY', Oracle will implicitly convert the string literal '01-JAN-19' to a date type to compare with insert_date.
B:is incorrect because if customer_id is a numeric data type, there is no need for implicit conversion. C is incorrect because using the DATE literal DATE '2019-01-01' is an explicit conversion. E is incorrect because TO_CHAR(customer_id) is an explicit conversion from a numeric to a string data type.
NEW QUESTION # 58
Examine this statement which executes successfully:
Which three are true?
A. Regardless of salary,only if the employee id is less than 125,insert EMPLOYEE_ID,NANAGER_ID,SALARY into the MGR_HISTORY table.
B. Regardless of salary and employee id,insert EMPLOYEE_ID,MANAGER_ID,and SALARY into the MGR_HISTORY table.
C. If the salary is 20000 or less and the employee id is less than 125,insert EMPLOYEE_ID,HIRE_DATE,and SALARY into the SAL_HISTORY table.
D. If the salary is more than 20000 and the employee is less than 125,insert EMPLOYEE_ID and SALARY into the SPECIAL_SAL table.
E. Only if the salary is 20000 or less and the employee id is less than 125,insert EMPLOYEE_ID,MANAGER_ID,and SALARY into the MGR_HISTORY table.
F. Only if the salary is 20000 or less and the employee id is 125 or higher,insert EMPLOYEE_ID,MANAGER_ID,and SALARY into the MDR_HISTORY table.
Answer: A,C,E
Explanation:
The question describes a scenario with multiple conditional statements about data manipulation based on certain criteria related to employee_id and salary. The options detail different conditions and corresponding actions (insertions into various tables). Given the conditions specified in each option, here are the accurate answers based on logical deduction as Oracle SQL does not directly define these scenarios; instead, it provides the mechanisms (like IF conditions, WHERE clauses, etc.) to implement such logic:
* Option A: Regardless of salary, only if the employee id is less than 125, insert EMPLOYEE_ID, MANAGER_ID, SALARY into the MGR_HISTORY table.
* This is logically plausible as it specifies a simple condition on the employee ID without regard to salary. If true, it directs an insertion of specific columns into a history table, which is a common practice for recording details of a subset of employees based on certain criteria (like employee_id in this case).
* Option C: Only if the salary is 20000 or less and the employee id is less than 125, insert EMPLOYEE_ID, MANAGER_ID, and SALARY into the MGR_HISTORY table.
* Similar to option A, this statement combines two conditions (on salary and employee_id), focusing on a specific subset of employees for history recording. The combined conditionality aligns with typical SQL practices for managing and logging specific data subsets based on multiple criteria.
* Option E: If the salary is 20000 or less and the employee id is less than 125, insert EMPLOYEE_ID, HIRE_DATE, and SALARY into the SAL_HISTORY table.
* This condition again deals with specific attributes (salary and employee_id) to determine which data (including the HIRE_DATE) goes into another history table. The inclusion of HIRE_DATE suggests tracking changes or states over time, which is common in employee management systems.
NEW QUESTION # 59
Examine the command:
What does ON DELETE CASCADE imply?
A. When a row in the BOOKStable is deleted, the rows in the BOOK_TRANSACTIONStable whose BOOK_IDmatches that of the deleted row in the BOOKStable are also deleted.
B. When the BOOKStable is dropped, the BOOK_TRANSACTIONStable is dropped.
C. When a value in the BOOKS.BOOK_IDcolumn is deleted, the corresponding value is updated in the BOOKS_TRANSACTIONS.BOOK_IDcolumn.
D. When the BOOKStable is dropped, all the rows in the BOOK_TRANSACTIONStable are deleted but the table structure is retained.
Answer: A
NEW QUESTION # 60
Which two statements are true regarding subqueries? (Choose two.)
A. Only two subqueries can be placed at one level.
B. There is no limit on the number of subquery levels in the WHERE clause of a SELECT statement.
C. A subquery can be used only in SQL query statements.
D. A subquery can retrieve zero or more rows.
E. A subquery can appear on either side of a comparison operator.
Answer: D,E
NEW QUESTION # 61
Choose two
Examine the description of the PRODUCT DETALS table:
A. PRODUCT_PRICE can be used in an arithmetic expression even if it has no value stored in it
B. EXPIRY_DATE cannot be used in arithmetic expressions.
C. EXPIRY_DATE contains the SYSDATE by default if no date is assigned to it
D. PRODUCT_NAME cannot contain duplicate values.
E. PRODUCT_PRICE contains the value zero by default if no value is assigned to it.
F. PRODUCT_ID can be assigned the PEIMARY KEY constraint.
Answer: A,F
Explanation:
* A. PRODUCT_ID can be assigned the PRIMARY KEY constraint.
In Oracle Database 12c, a PRIMARY KEY constraint is a combination of a NOT NULL constraint and a unique constraint. It ensures that the data contained in a column, or a group of columns, is unique among all the rows in the table and not null. Given the PRODUCT_ID is marked as NOT NULL, it is a candidate for being a primary key because we can assume that it is intended to uniquely identify each product in the table.
NEW QUESTION # 62
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