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Free PDF Quiz 2026 Oracle 1z0-071: Useful Oracle Database SQL Exam Dumps

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Free PDF Quiz 2026 Oracle 1z0-071: Useful Oracle Database SQL Exam Dumps

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Oracle Database SQL Sample Questions (Q173-Q178):NEW QUESTION # 173
Which two statements are true regarding the execution of the correlated subqueries? (Choose two.)
  • A. The nested query executes after the outer query returns the row.
  • B. The nested query executes first and then the outer query executes.
  • C. The outer query executes only once for the result returned by the inner query.
  • D. Each row returned by the outer query is evaluated for the results returned by the inner query.
Answer: A,D

NEW QUESTION # 174
Examine the description of the PRODUCT_INFORMATION table:

  • A. SELECT (COUNT(list_price) FROM Product_intormation WHERE list_price=NULL;
  • B. BELECT COUNT(list_price) FROM product_information where list_price is NULL;
  • C. SELECT COUNT(DISTINCT list_price) FROM product_information WHERE list_price is null.
  • D. SELECT count(nvl( list_price,0)) FROM product_information WHERE list_price is null;
Answer: D
Explanation:
In SQL, when you want to count occurrences of null values using the COUNT function, you must remember that COUNT ignores null values. So, if you want to count rows with null list_price, you have to replace nulls with some value that can be counted. This is what the NVL function does. It replaces a null value with a specified value, in this case, 0.
A, C, and D options attempt to count list_price directly where it is null, but this will always result in a count of zero because COUNT does not count nulls. Option B correctly uses the NVL function to convert null list_price values to 0, which can then be counted. The WHERE list_price IS NULL clause ensures that only rows with null list_price are considered.
The SQL documentation confirms that COUNT does not include nulls in its count and NVL is used to substitute a value for nulls in an expression. So option B will give us the correct count of rows with a null list_price.

NEW QUESTION # 175
Evaluate the following query:
SQL> SELECT TRUNC (ROUND (156.00, -1),-1)
FROM DUAL;
What would be the outcome?
  • A. 0
  • B. 1
  • C. 2
  • D. 3
  • E. 4
Answer: C

NEW QUESTION # 176
Examine the description of the ORDERS table:

Which three statements execute successfully?
  • A. SELECT order_ id, order_ data FROM orders
    UNION ALL
    SELECT invoice_ id, invoice_ data FROM invoices ORDER BY order_ id;
  • B. SELECT * FROM orders
    MINUS
    SELECT * FROM INVOICES ORDER BY 1
  • C. (SELECT * FROM orders
    UNION ALL
    SELECT* FROM invoices) ORDER BY order _id;
  • D. SELECT order_ id, invoice_ data order_ date FROM orders
    MINUS
    SELECT invoice_ id, invoice_ data FROM invoices ORDER BY invoice_ id;
  • E. SELECT * FROM orders ORDER BY order_ id
    UNION
    SELECT * FROM invoices;
  • F. SELECT * FROM orders ORDER BY order_ id
    INTERSEOT
    SELECT * FROM invoices ORDER BY invoice_ id;
  • G. SELECE order _id, order _ date FRON orders
    LNTERSECT
    SELECT invoice_ id, invoice_ id, order_ date FROM orders
Answer: A,B,C

NEW QUESTION # 177
Examine the structure of the MARKStable:

Which two statements would execute successfully? (Choose two.)
SELECT SUM(DISTINCT NVL(subject1,0)), MAX(subject1)
  • A. FROM marks
    WHERE subject1 > AVG(subject1);
    SELECT SUM(subject1+subject2+subject3)
  • B. FROM marks
    WHERE student_name LIKE 'R%';
  • C. FROM marks
    WHERE subject1 > subject2;
    SELECT student_name subject1
  • D. FROM marks
    WHERE student_name IS NULL;
    SELECT student_name,SUM(subject1)
Answer: C,D

NEW QUESTION # 178
......
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