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[General] Certification 1z0-071 Questions - 1z0-071 Cheap Dumps

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【General】 Certification 1z0-071 Questions - 1z0-071 Cheap Dumps

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Oracle Database SQL Sample Questions (Q110-Q115):NEW QUESTION # 110
Sales data of a company is stored in two tables, SALES1 and SALES2, with some data being duplicated across the tables. You want to display the results from the SALES1 table, which are not present in the SALES2 table.
SALES1 table
NameNullType
-----------------------------------------------
SALES_IDNUMBER
STORE_IDNUMBER
ITEMS_IDNUMBER
QUANTITYNUMBER
SALES_DATEDATE
SALES2 table
NameNullType
----------------------------------------------
SALES_IDNUMBER
STORE_IDNUMBER
ITEMS_IDNUMBER
QUANTITYNUMBER
SALES_DATEDATE
Which set operator generates the required output?
  • A. UNION
  • B. MINUS
  • C. SUBTRACT
  • D. PLUS
  • E. INTERSECT
Answer: B
Explanation:
Explanation
References:
https://docs.oracle.com/cd/B1930 ... 4200/queries004.htm

NEW QUESTION # 111
View the exhibit and examine the data in the PROJ_TASK_DETAILS table. (Choose the best answer.)

The PROJ_TASK_DETAILS table stores information about project tasks and the relation between them.
The BASED_ON column indicates dependencies between tasks.
Some tasks do not depend on the completion of other tasks.
You must generate a report listing all task IDs, the task ID of any task upon which it depends and the name of the employee in charge of the task upon which it depends.
Which query would give the required result?
  • A. SELECT p.task_id, p.based_on, d.task_in_chargeFROM proj_task_details p JOIN proj_task_details dON (p.based_on = d.task_id);
  • B. SELECT p.task_id, p.based_on, d.task_in_chargeFROM proj_task_details p FULL OUTER JOIN proj_task_details dON (p.based_on = d.task_id);
  • C. SELECT p.task_id, p.based_on, d.task_in_chargeFROM proj_task_details p JOIN proj_task_details dON (p.task_id = d.task_id);
  • D. SELECT p.task_id, p.based_on, d.task_in_chargeFROM proj_task_details p LEFT OUTER JOIN proj_task_details dON (p.based_on = d.task_id);
Answer: D

NEW QUESTION # 112
Which two statements will return the names of the three employees with the lowest salaries?
  • A. SELECT last_ name, salary
    FROM employees
    FETCH FIRST 3 ROWS ONLY
    ORDER BY salary;
  • B. SELECT last_ name, salary
    FROM employees
    WHERE ROWNUM <=3
    ORDER BY salary
  • C. SELECT last_ name, salary
    FROM
    (SELECT" FROM employees ORDER BY salary)
    WHERE ROWNUM <=3
  • D. SELECT last name, salary
    FROM employees
    ORDER BY salary
    FETCE FIRST 3 RONS ONLY;
  • E. SELECT last_ name, salary
    FBOM employees
    WEERE
    ORDER BY SELECT
    ROINUM <= 3
    salary FROM
    employees);
Answer: A,C
Explanation:
A: This statement is correct. It orders the employees by salary and fetches the first 3 rows.
B: This statement has a typo with "FETCE" and "RONS" which should be "FETCH" and "ROWS". Hence, it will not execute successfully.
C: This statement will not execute successfully due to syntactical errors and incorrect use of the ORDER BY clause.
D: This statement is correct. It uses a subquery to order employees by salary and then limits the results to the first 3 using the ROWNUM pseudo-column.
E: This statement will not execute successfully because ROWNUM is evaluated before the ORDER BY clause, so it would return the first 3 rows based on the table's natural order, not the lowest salaries.
The behavior of ROWNUM and the FETCH FIRST syntax are explained in the Oracle Database SQL Language Reference 12c.

NEW QUESTION # 113
Evaluate the following SQL statement:
SQL> select cust_id, cust_last_name "Last name"
FROM customers
WHERE country_id = 10
UNION
SELECT cust_id CUST_NO, cust_last_name
FROM customers
WHERE country_id = 30
Identify three ORDER BY clauses either one of which can complete the query.
  • A. ORDER BY 2, 1
  • B. ORDER BY "Last name"
  • C. ORDER BY 2, cust_id
  • D. ORDER BY "CUST_NO"
  • E. ORDER BY CUST_NO
Answer: A,B,C
Explanation:
Explanation
Using the ORDER BY Clause in Set Operations
-The ORDER BY clause can appear only once at the end of the compound query.
-Component queries cannot have individual ORDER BY clauses.
-The ORDER BY clause recognizes only the columns of the first SELECT query.
-By default, the first column of the first SELECT query is used to sort the output in an ascending order.

NEW QUESTION # 114
The PROD_ID column is the foreign key in the SALES table.Which references the PRODUCTS table.
Similarly,the CUST_ID and TIME_ID columns are Also foreign keys in the SALES table referencing the CUSTOMERS and TIMES tables, respectively.
Evaluate the following CREATE TABLE command:
CREATE TABLE new_sales(prod_id, I cust_id, order_date DEFAULT SYSDATE)
AS SELECT I prod_id,cust_id,time_id FROM sales.
Which statement is true regarding the above command?
  • A. The NEW_SALES table would get created and all the NOT NULL constraints defined on the specified columns would be passed to the new table.
  • B. The NEW_SALES table would get created and all the FOREIGN KEY constraints defined on the specified columns would be passed to the new table
  • C. The NEW_SALES table would not get created because the column names in the CREATE TABLE command and the SELECT clause I do not match.
  • D. The NEW_SALES table would not get created because the DEFAULT value cannot be specified in the column definition.
Answer: C
Explanation:
The statement true regarding the CREATE TABLE command:
* C. The NEW_SALES table would not get created because the column names in the CREATE TABLE command and the SELECT clause do not match: The SQL command tries to create a table with columns prod_id, cust_id, and order_date, but the SELECT statement specifies columns prod_id
, cust_id, and time_id. The mismatch in column names and the number of columns specified will prevent the table from being created.
Incorrect options:
* A: It is possible to specify a DEFAULT value in the column definition when creating a table with the CREATE TABLE AS SELECT syntax.
* B: Not all NOT NULL constraints (or any other constraints, for that matter) are automatically passed to the new table unless explicitly stated in the CREATE TABLE statement.
* D: FOREIGN KEY constraints are not automatically included when creating a table using the CREATE TABLE AS SELECT syntax; they would need to be added explicitly afterwards.

NEW QUESTION # 115
......
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