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[General] Certification 1Z0-106 Cost, 1Z0-106 Latest Test Practice

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【General】 Certification 1Z0-106 Cost, 1Z0-106 Latest Test Practice

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Oracle 1Z0-106 Exam, also known as Oracle Linux 8 Advanced System Administration, is a certification exam designed for IT professionals who want to validate their advanced knowledge and skills in managing and administering Oracle Linux 8 systems. 1Z0-106 exam is intended for individuals who have already passed the Oracle Linux 8 System Administration exam and have experience in Linux system administration.
Oracle Linux 8 Advanced System Administration Sample Questions (Q47-Q52):NEW QUESTION # 47
Which two components are used for creating a new rsyslog rule?
  • A. action
  • B. parser
  • C. filter
  • D. module
  • E. security policy
Answer: A,C

NEW QUESTION # 48
Examine the access privileges on this directory:
drwx------ 2 user1 test 4096 Nov 6 10:12 my_directory/
You must enable another user to read and navigate to my_directory. Which command will do this?
  • A. setfacl --modify group:test:r-- my_directory
  • B. setfacl --modify user:user2:r-- my_directory
  • C. setfacl --default --modify user:user2:rw- my_directory
  • D. setfacl --modify user:user2:r-x my_directory
  • E. setfacl -x user:user2 my_directory
Answer: D
Explanation:
* Option D (Correct):The commandsetfacl --modify user:user2:r-x my_directorysets an Access Control List (ACL) entry that givesuser2read (r) and execute (x) permissions onmy_directory. The execute (x) permission is required to allow navigation into the directory.
* Option A (Incorrect):The--defaultoption would set the default ACL for future files or directories created withinmy_directory, not the directory itself.
* Option B (Incorrect):This option gives only read (r) permission, but without execute (x) permission, user2cannot navigate into the directory.
* Option C (Incorrect):The-xoption is used to remove an ACL entry, not modify it.
* Option E (Incorrect):This modifies the ACL for the grouptestinstead of the useruser2.
Oracle Linux Reference:Refer to:
* OracleLinux 8: Using Access Control Lists

NEW QUESTION # 49
Which statement is true about slice units?
  • A. The system.slice contains all system services and user sessions.
  • B. Processes in a slice unit are named at the same level as scopes and services.
  • C. A slice unit accepts multiple names by the creation of additional symlinks to the unit file.
  • D. A slice unit is a concept for hierarchically managing resources in a group of processes.
Answer: D

NEW QUESTION # 50
Examine this command:
# auditctl -w /etc/passwd -p w -k pass
Which two statements are true upon execution?
  • A. An audit rule is defined that creates a log entry every time /etc/passwd is read.
  • B. An audit rule is defined with the keyword pass.
  • C. A write occurs to /etc/audit/rules.d/audit.rules.
  • D. An audit is defined that creates a log entry every time a write occurs to /etc/passwd.
  • E. A write occurs to /etc/audit/audit.rules.
Answer: B,D
Explanation:
* Option C (Correct):The-k passpart of theauditctlcommand defines a keyword (pass) for the audit rule.
This keyword helps in filtering and searching logs in the audit trail.
* Option D (Correct):The-w /etc/passwd -p wpart of the command sets up a watch on the/etc/passwdfile for write (w) operations. This audit rule will generate a log entry every time there is a write operation to
/etc/passwd.
* Option A (Incorrect):This command does not write directly to/etc/audit/rules.d/audit.rules; it defines a rule in memory that could be saved to this file later.
* Option B (Incorrect):The rule only logs write (w) operations; it does not log read operations.
* Option E (Incorrect):The command does not directly cause a write to/etc/audit/audit.rules.
Oracle Linux Reference:Refer to:
* OracleLinux 8: Auditing and System Logs
* man auditctlfor details on audit rules and options.

NEW QUESTION # 51
Which command configures a fully functional and accessible interface on VLAN 800?
  • A. modprobe 8021q ip link add link eth0 name eth0.800 type vlan id 800 ip address add 10.135.1.120/24 dev eth0.800 ip link set eth0.800 up
  • B. modprobe 8021q ip link add link eth0 name eth0.800 type vlan id 800 ip link set eth0.800 up
  • C. modprobe 8021q ip link add link eth0 name eth0.800 VLAN 800 ip address add 10.135.1.120/24 dev eth0.800 ip link set eth0.800 up
  • D. modprobe 8021q ip address add 10.135.1.120/24 dev eth0.800 ip link set eth0.800 up
Answer: A

NEW QUESTION # 52
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