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[General] Pass Guaranteed 2026 1z0-071: Valid Oracle Database SQL Valid Real Test

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【General】 Pass Guaranteed 2026 1z0-071: Valid Oracle Database SQL Valid Real Test

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Oracle Database SQL Sample Questions (Q240-Q245):NEW QUESTION # 240
View the exhibits and examine the structures of the COSTS and PROMOTIONS tables.


Evaluate the following SQL statement:
SQL> SELECT prod_id FROM costs
WHERE promo_id IN (SELECT promo_id FROM promotions
WHERE promo_cost < ALL
(SELECT MAX(promo_cost) FROM promotions
GROUP BY (promo_end_date-
promo_begin_date)));
What would be the outcome of the above SQL statement?
  • A. It displays prod IDs in the promos with the lowest cost in the same time interval.
  • B. It displays prod IDs in the promos with the highest cost in the same time interval.
  • C. It displays prod IDs in the promo with the lowest cost.
  • D. It displays prod IDs in the promos which cost less than the highest cost in the same time interval.
Answer: D

NEW QUESTION # 241
Examine this statement:

Which two things must be changed for it to execute successfully?
  • A. The primary key constraint on BMP_ID must have a name.
  • B. The word CONSTRAINT in the foreign key constraint on DEPT_ID must be changed to FOREIGN KEY.
  • C. One of the LONG columns must be changed to a VARCHAR2 or CLOB.
  • D. The NOT NULL constraint on ENAME must be defined at the column level instead of the table level.
  • E. The foreign key constraint on DEPT_ID must be defined at the table level instead of the column level.
Answer: C,D

NEW QUESTION # 242
Which statement is true regarding the INTERSECToperator?
  • A. It ignores NULLvalues.
  • B. The names of columns in all SELECTstatements must be identical.
  • C. Reversing the order of the intersected tables alters the result.
  • D. The number of columns and data types must be identical for all SELECTstatements in the query.
Answer: D
Explanation:
Explanation/Reference:
Explanation:
INTERSECT Returns only the rows that occur in both queries' result sets, sorting them and removing duplicates.
The columns in the queries that make up a compound query can have different names, but the output result set will use the names of the columns in the first query.

NEW QUESTION # 243
Examine the description of the PRODUCT_ STATUS table:

The STATUS column contains the values IN STOCK or OUT OF STocK for each row.
Which two queries will execute successfully?
  • A. SELECT prod_id q's not available" from product_ status WHERE status = 'OUT OF STOCK';
  • B. SELECT prod_id ||q'(' s not available)' 'CURRENT AVAILABILITY' FROM
    product_ status WHERE status = 'OUT OF STOCK'
  • C. SELECT PROD_ID||q'('s not available)' "CURRENT AVAILABILITY"
    FROM product_ status WHERE status = 'OUT OF STOCK';
  • D. SELECT PROD_ID||q'('s not available)' FROM
    product_ status WHERE status = 'OUT OF STOCK';
  • E. SELECT prod_id "CURRENT AVAILABILITY"||q' ('s not available)' from product_ status WHERE status
    = 'OUT OF STOCK';
  • F. SELECT prod_id ||q"' s not available" FROM
    product_ status WHERE status = 'OUT OF STOCK';
Answer: C,D

NEW QUESTION # 244
Examine the structure of the EMPLOYEES table.

There is a parent-child relationship between EMPLOYEE_ID and MANAGER_ID.
You want to display the last names and manager IDs of employees who work for the same manager as the employee whose EMPLOYEE_ID is 123.
Which query provides the correct output?
  • A. SELECT e.last_name, m.manager_idFROM employees e LEFT OUTER JOIN employees mon (e.employee_id = m.manager_id)WHERE e.employee_id = 123;
  • B. SELECT m.last_name, e.manager_idFROM employees e LEFT OUTER JOIN employees mon (e.manager_id = m.manager_id)WHERE e.employee_id = 123;
  • C. SELECT e.last_name, e.manager_idFROM employees e RIGHT OUTER JOIN employees mon (e.employee_id = m.employee_id)WHERE e.employee_id = 123;
  • D. SELECT e.last_name, m.manager_idFROM employees e RIGHT OUTER JOIN employees mon (e.manager_id = m.employee_id)AND e.employee_id = 123;
Answer: B

NEW QUESTION # 245
......
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