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[General] Pass Guaranteed 2026 Fantastic C_ABAPD_2507: Practice Test SAP Certified Associa

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【General】 Pass Guaranteed 2026 Fantastic C_ABAPD_2507: Practice Test SAP Certified Associa

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SAP Certified Associate - Back-End Developer - ABAP Cloud Sample Questions (Q51-Q56):NEW QUESTION # 51
You want to join two database tables, T_CARRIER, and T_CONNECTIONS, to retrieve all carriers, whether they have corresponding connections or not.
Which statements would achieve this? Note: There are 2 correct answers to this question.
  • A. SELECT FROM carrier INNERR JOIN t_connections ON...
  • B. SELECT FROM connections RIGHT OUTER JOIN t_carrier ON...
  • C. SELECT FROM carrier LEFT INNER JOIN t_connectionsON..
  • D. SELECT FROM carrier LEFT OUTER JOIN t_connectionsON...
Answer: B,D

NEW QUESTION # 52
Which of the following results in faster access to internal tables? (Select 3 correct answers)
  • A. In a sorted internal table, specifying the primary key completely.
  • B. In a sorted internal table, specifying the primary key partially from the left without gaps.
  • C. In a hashed internal table, specifying the primary key completely.
  • D. In a standard internal table, specifying the primary key partially from the left without gaps.
  • E. In a hashed internal table, specifying the primary key partially from the left without gaps.
Answer: A,B,C
Explanation:
Comprehensive and Detailed Explanation From Exact Extract:
* Sorted tables:
* Full key lookup uses a binary search # efficient (A).
* Left-aligned partial key lookup also benefits from sort order to find ranges efficiently (C).
* Hashed tables:
* Require the complete key for O(1) access; partial key is not supported. Hence (E) is correct and (D) is not.
* Standard tables:
* Have no inherent ordering/index for key-based access; specifying a key (even partially) results in linear search unless you maintain sort and specify BINARY SEARCH explicitly, which still doesn't change the fundamental case in this question; thus (B) is not considered a faster pattern here.
Study Guide Reference: ABAP Cloud Programming-Internal Tables (standard/sorted/hashed) performance characteristics.

NEW QUESTION # 53
Which patterns raise an exception? Note: There are 3 correct answers to this question.
  • A. DATA: gv_target TYPE c LENGTH 5. V □ CONSTANTS: ECO string TYPE string VALUE 0123456789ABCDEF". gv_target - EXACT (gco_string + 5 (6) ).
  • B. DATA: gv_target TYPE p DECIMALS 2. CONSTANTS: go intl TYPE i VALUE 3. gv_target -U EXACT (2 gcojntl).
  • C. DATA: gv_target TYPE d. s/ □ CONSTANTS: gco_date TYPE d VALUE '20331233*. gv_target EXACT ( geo_date).
  • D. DATA: Ev target TYPE p DECIMALS 3. CONSTANTS: gcojntl TYPE i VALUE 2. Ev_target -U EXACT #2 / gcojntl ).
  • E. DATA: gv_target TYPE string. □ CONSTANTS: gco_string TYPE LENGTH 16 VALUE 0123456789ABCDEF*. gv_target = EXACT # gco_string+5 (5) ).
Answer: A,B,C
Explanation:
The patterns that raise an exception are those that use the constructor operator EXACT to perform a lossless assignment or calculation, but the result cannot be converted to the target data type without data loss. The following are the explanations for each pattern:
A: This pattern raises the exception CX_SY_CONVERSION_LOST because the result of the calculation 2 * 3 is 6, which cannot be assigned to a packed number with two decimal places without losing the integer part. The operator -U is used to perform a lossless calculation with the calculation type decfloat34.
B: This pattern does not raise an exception because the result of the substring expression gco_string+5(5) is '6789A', which can be assigned to a string without data loss. The operator EXACT # is used to perform a lossless assignment with the data type of the argument.
C: This pattern raises the exception CX_SY_CONVERSION_LOST because the result of the substring expression gco_string+5(6) is '6789AB', which cannot be assigned to a character field with length 5 without losing the last character. The operator EXACT is used to perform a lossless assignment with the data type of the target field.
D: This pattern does not raise an exception because the result of the calculation 2 / 2 is 1, which can be assigned to a packed number with three decimal places without data loss. The operator -U is used to perform a lossless calculation with the calculation type decfloat34.
E: This pattern raises the exception CX_SY_CONVERSION_ERROR because the constant gco_date contains an invalid value '20331233' for a date data type, which cannot be converted to a valid date. The operator EXACT is used to perform a lossless assignment with the data type of the target field.

NEW QUESTION # 54
You have a superclass super1 and a subclass sub1 of super1. Each class has an instance constructor and a static constructor. The first statement of your program creates an instance of sub1.
In which sequence will the constructors be executed?
  • A. Instance constructor of super1 # Class constructor of super1 # Class constructor of sub1 # Instance constructor of sub1
  • B. Class constructor of sub1 # Instance constructor of super1 # Instance constructor of sub1 # Class constructor of super1
  • C. Class constructor of super1 # Class constructor of sub1 # Instance constructor of super1 # Instance constructor of sub1
  • D. Instance constructor of sub1 # Instance constructor of super1 # Class constructor of super1 # Class constructor of sub1
Answer: C
Explanation:
Comprehensive and Detailed Explanation from Exact Extract:
Execution order when creating an instance of a subclass:
* Class constructor of the superclass (super1) executes first.
* Class constructor of the subclass (sub1) executes second.
* Then the instance constructor of the superclass (super1) executes.
* Finally, the instance constructor of the subclass (sub1) executes.
This sequence guarantees that both the static (class-level) and instance-level initializations of the superclass are complete before the subclass is constructed.
Verified Study Guide Reference: ABAP Objects Programming Guide - Class and Instance Constructor Execution Order.

NEW QUESTION # 55
In a class you use the statement DATA var TYPE ...
What may stand in place of the type?
(Select 2 correct answers)
  • A. The name of a data element from the ABAP Dictionary
  • B. The name of a type defined privately in class ZCL_CLASS_A
  • C. The name of a type defined privately in another class
  • D. The name of a domain from the ABAP Dictionary
Answer: A,B
Explanation:
Comprehensive and Detailed Explanation from Exact Extract:
The ABAP DATA statement declares a variable with an assigned type.
* A. Private type in the same class (ZCL_CLASS_A) # # Allowed. A class can use its own local type definitions, declared using TYPES.
* B. Domain from ABAP Dictionary # # Not allowed directly. Domains define technical attributes but cannot be referenced directly in DATA; they must be wrapped in a data element.
* C. Type defined privately in another class # # Not accessible, since private definitions are encapsulated.
* D. Data element from ABAP Dictionary # # Allowed, because data elements are global dictionary objects.
This follows ABAP Cloud extensibility rules, ensuring encapsulation and strict typing.
Verified Study Guide Reference: ABAP Dictionary Development Guide, ABAP Cloud Back-End Developer Learning Material (Variable Typing and Encapsulation).

NEW QUESTION # 56
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