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[Hardware] CEM Valid Test Cram, CEM Sample Questions

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【Hardware】 CEM Valid Test Cram, CEM Sample Questions

Posted at yesterday 02:40      View：19 | Replies：0        Print      Only Author   [Copy Link] 1#
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The AEE is committed to making the AEE CEM certification exam journey simple, smart, and easiest. The mock Certified Energy Manager (CEM) exams that will give you real-time environment for AEE CEM exam preparation. To keep you updated with latest changes in the CEM Test Questions, we offer one-year free updates in the form of new questions according to the requirement of CEM real exam. Updated CEM PDF dumps ensure the accuracy of learning materials and guarantee success of in your first attempt.
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AEE Certified Energy Manager (CEM) Sample Questions (Q10-Q15):NEW QUESTION # 10
An outdoor parking area has 25 light poles. Each pole has a 420 Watt (ballast included) high-pressure sodium (HPS) luminaire. The parking area lights are illuminated 4,500 hours per year and the electricity cost is $0.08
/kWh. What is the annual energy cost reduction if each luminaire is replaced with a 220-Watt (driver included) LED luminaire?
  • A. $1,200/yr
  • B. $1,800/yr
  • C. $1,500/yr
  • D. $2,600/yr
  • E. $2,200/yr
Answer: B
Explanation:
To determine the annual energy cost savings from switching to LED luminaires:
A table with numbers and symbols AI-generated content may be incorrect.


NEW QUESTION # 11
A heat pump water heater has an annual average coefficient of performance (COP) of 2.1 and heats water from 15°C to 50°C. Hot water use is 100 liters per day, 365 days/yr. The electricity cost is $0.10/kWh. What is the annual water heating cost? (The specific heat of water (C) is 4.2 kJ/kg-°C.)
  • A. $70.97/year
  • B. $64.66/year
  • C. $44.88/year
  • D. $52.20/year
  • E. $88.29/year
Answer: B

NEW QUESTION # 12
In a typical compressed air system, energy can be saved by which of the following actions?
  • A. Reducing the capacity of the compressed air receiver tanks
  • B. Decreasing supply air pressure
  • C. Raising the air pressure
  • D. Reducing the air distribution pipe size
  • E. Move the inlet air filter to a warmer location
Answer: C

NEW QUESTION # 13
A facility has a monthly peak power demand of 1,000 kW and an average power factor of 80%. The facility pays a demand charge of $7.50/kVA-month. What is the additional cost per month because the power factor is less than 100%?
  • A. $1,875/month
  • B. $0/month
  • C. $2,244/month
  • D. $3,370/month
  • E. $187/month
Answer: A
Explanation:
To calculate the additional cost due to a power factor of less than 100%, follow these steps:
Step 1: Convert Real Power (kW) to Apparent Power (kVA)

Step 2: Compute Additional kVA Due to Power Factor


NEW QUESTION # 14
A steam trap with a 6-mm orifice in an 0.8-MPa steam system has failed open. The steam system is pressurized 8.760 hours/yr. The steam cost is $15.00 /GJ. Using the table below, what is the annual cost of the vented steam through the failed steam trap? ignore any condensate return issues.

[The question from the previous image, which was about calculating the annual cost of heat loss through a wall, but had a discrepancy between the calculated cost and the provided answer choices]
  • A. $10,000/yr
  • B. $5,000/yr
  • C. $40,000/yr
  • D. $20,000/yr
  • E. $30,000/yr
Answer: E

NEW QUESTION # 15
......
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